Two particles of equal mass m are projected form the ground with speed v 1 and v 2 at angle θ 1 and θ 2 ( θ 1 , θ 2 ≠ 0, 180º) as shown in figure. The centre of mass of the two particles
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Centre of mass will move in a vertical line if v 1 cos θ 1 = v 2 cos θ 2 . Otherwise for any other values it will follow a parabolic path.
= V 1 cos θ 1 
+ (V 1 sin θ 1 – gt) 
Parabolic path
= – V 2 cos θ 2 
+ (V 2 sin θ 2 – gt) 
Parabolic path
m 1 = m 2 = m
= 
= 
v 1 cos θ 1 – v 2 cos θ 2 = 0 ⇒ v 1 cos θ 1 = v 2 cos θ 2
then path may be straight line.
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